Respuesta :

mathmate
Amount borrowed, P = 13000
Interest, i = 0.07/12 per month
number of periods (months),  n = 4*12 = 48

Monthly payment, 
[tex]A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}[/tex]
[tex]=\frac{13000(.07/12*(1+.07/12)^{48}}{(1+.07/12)^{48}-1}[/tex]
=311.30   (to the nearest cent)

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