Respuesta :

DeanR
[tex]x = 4z[/tex]

[tex]2y = 4z[/tex]

Dividing both sides by two,

[tex]y = 2z[/tex]

OK, part 1.

[tex]x+4y+z = 4z + 4(2z) +z = 13z[/tex]

When [tex]z=2[/tex] then [tex]x+4y+z =13(2)=26[/tex]

Part 2.

[tex]2x+3y+2z= 2(4z) +3(2z) + 2z = 16z[/tex]

When [tex]z=2[/tex] then [tex]2x+3y+2z=16(2)=32[/tex]


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